An underrated topic among distribution operators is the calculation of headloss. Determining the headloss is very important in transporting water in Kentucky, whether it is for a collection system or distribution. With the different types of terrains and various elevations represented in Kentucky, this could be a critical step in staying in compliance with pressures that must be provided in the distribution system.
Let’s calculate the total headloss of a pipeline using the C-Factor.
What is the total headloss for two miles of 10-inch pipeline if the C-Factor is 100, the flow rate is 240 gpm, and there is a 60-foot incline or elevational change?
Total Head = Elevational Head + Velocity Head
10,560 feet of pipe for the two miles
Dividing the total length of pipe needed by 100-foot sections, gives you 105.6 100-foot sections.
So 105.6 x .07 = 7.39 ft.
60 ft. of elevational head + 7.39 ft. friction head = 67.39 ft. of head total
67.39 ft. of head x .433 = 29.18 psi.
Check out the Test Your Knowledge – Calculating Headloss post for additional practice problems.